Question.3746 - Homework for chapter 9
Answer Below:
Homework Assignment for Exam 2 PHY 100- Fall 2024 Chapter 9 Problems due 10/18/24 1) P = e/a F = 60 N, A = 0.4 m2 P = 60 / 0.4 = 150 pa. 4) F = P x A P = 520 Pa, A = 0.3 m2 = 520 x 0.3 = 156 N. 6) (F2 / F1) = (A2 / A1) F2 = 6160 N, A2 / A1 = 70 F1 = F2 / 70 = 6160 / 70 = 88 N. 8) Boyles law = P1V1 = P2V2 P1 = 8 kPa, P2? = 40 kPa, V1? = 0.75 m3 V1 = P1V1 /? P2 = (8 x 0.75) / 40 = 0.15 m3 12) m = ?VV = 8.3 m3 Water density, ? = 1000?kg / m3 m = 1000 x 8.3 kg / m3 = 8300 kg Buoyant force Fb = m ? g = 8300 ? 9.8 = 81340 N 13) Fb = ?VgV = 0.3 m3, ? = 1000 kg / m3 Fb = 1000 ? 0.3 ? 9.8 = 2940 N 14) continuity equation: A1v1 = A2v2 v1 = 3.5 m/s A2 = A1/2 V2 = (A1/A2) x v1 = 2 x 3.5 = 7 m/s 16) ?P = A/F F = 90,000 N, A = 8 m2 ??P = 90,000 / 8 = 11,250 Pa Sp3) V = side3 = (0.04)3 M = ?V = 8960 ? 0.000064 = 0.573 kg W = mg = 0.573 ? 9.8 = 5.615?N Fb?= ?water? ? V ? g = 1000 ? 0.000064 ? 9.8 = 0.6272 N T = W Fb = 5.615 ? 0.6272 = 4.9878 N Sp5) A1 ?= ? ? (0.045)2 = 0.00636 m2 A2 ?= ? ? (0.026)2 = 0.00212 m2 A1V1 = A2V2 V2 = (A1/A2) x V1 = (0.00212 / 0.00636) x 1.6 = 4.8 m/s Pressure in narrow portion: The pressure in the narrow portion is less due to increased velocity (Bernoulli's principle).More Articles From Science
.ico)
.ico)
.ico)
.ico)
